Model 4 Working with Man, Woman, Child Practice Questions Answers Test with Solutions & More Shortcuts
time & work PRACTICE TEST [7 - EXERCISES]
Model 1 Basics on Time & Work
Model 2 Formula method ‘M1D1W1 = M2D2W2’
Model 3 Man leaves & joins
Model 4 Working with Man, Woman, Child
Model 5 Split & Fraction of work
Model 6 Efficiency of the worker
Model 7 Working with individual wages
Question : 11 [SSC CHSL 2013]
If 4 men or 6 women can do a piece of work in 12 days working 7 hours a day; how many days will it take to complete a work twice as large with 10 men and 3 women working together 8 hours a day?
a) 8 days
b) 6 days
c) 7 days
d) 10 days
Answer »Answer: (c)
Using Rule 1,
4 men ≡ 6 women
1 men ≡ $6/4 = 3/2$ women
10 men + 3 women
= $10 × 3/2 + 3 = 18$ women
${M_1D_1T_1}/W_1 = {M_2D_2T_2}/W_2$
${6 × 12 × 7}/1 = {18 × D_2 × 8}/W_2$
$D_2 = {6 × 12 × 7 × 2}/{18 × 8}$ = 7 days
Question : 12 [SSC CHSL 2014]
3 men or 7 women can do a piece of work in 32 days. The number of days required by 7 men and 5 women to do a piece of work twice as large is
a) 27
b) 19
c) 21
d) 36
Answer »Answer: (c)
3 men ≡ 7 women
7 men ≡ ${7 × 7}/3 = 49/3$ women
7 men + 5 women = $(49/3 + 5)$ women
= $({49 + 15}/3)$ women = $64/3$ women
${M_1D_1}/W_1 = {M_2D_2}/W_2$
${7 × 32}/1 = {64 × D_2}/{3 × 2}$
$D_2 = {7 × 32 × 3 × 2}/64$ = 21 days
Using Rule 12,
Here, A = 3, B = 7, a = 32
$A_1 = 7, B_1$ = 5
Required time = $a/{A_1/A + B_1/B}$
= $32/{7/3 + 5/7} = 32/64 × 21 = 21/2$
They do the twice work in
$21/2$ × 2 = 21 days
Question : 13 [SSC CGL Tier-I 2012]
3 men and 4 boys can complete a piece of work in 12 days. 4 men and 3 boys can do the same work in 10 days. Then 2 men and 3 boys can finish the work in
a) 8 days
b) 17$1/2$ days
c) 5$5/11$ days
d) 22 days
Answer »Answer: (b)
12(3 men + 4 boys) ≡ 10 (4 men + 3 boys)
36 men + 48 boys = 40 men + 30 boys
4 men = 18 boys ⇒ 2 men = 9 boys
4 men + 3 boys
= 21 boys, who do the work in 10 days and
2 men + 3 boys = 12 boys
$M_1D_1 = M_2D_2$
21 × 10 = 12 × $D_2$
$D_2 = {21 × 10}/12 = 35/2 = 17{1}/2$ days
Using Rule 11,
Here, $A_1 = 3, B_1 = 4, D_1$ = 12
$A_2 = 4, B_2 = 3, D_2$ = 10
$A_3 = 2, B_3$ = 3
Required time = ${D_1D_2(A_1B_2 - A_2B_1)}/{D_1(A_1B_3 - A_3B_1) - D_2(A_2B_3 - A_3 B_2)}$ days
= ${12 × 10(3 × 3 - 4 × 4)}/{12(3 × 3 - 2 × 4) - 10(4 × 3 - 2 × 3)}$
= ${120 × - 7}/{12(9 - 8) - 10 × 6}$
= $ {-840}/{-48} = 17{1}/2$ days
Question : 14 [SSC CGL Tier-I 2013]
If 8 men or 12 boys can do a piece of work in 16 days, the number of days required to complete the work by 20 men and 6 boys is
a) 8$1/3$ days
b) 5$1/3$ days
c) 6$1/3$ days
d) 7$1/3$ days
Answer »Answer: (b)
8 men ≡ 12 boys ⇒ 4 men ≡ 6 boys
20 men ≡ 30 boys
20 men + 6 boys = 36 boys
$M_1D_1 = M_2D_2$
12 × 16 = 36 × $D_2$
$D_2 = {12 × 16}/36 = 16/3 = 5{1}/3$ days
Using Rule 12,
Here, A = 8, B = 12, a = 16
$A_1 = 20, B_1$ = 6,
Required number of days = $a/{A_1/A + B_1/B} = 16/{20/8 + 6/12}$
= $16/{5/2 + 1/2} = {16 × 2}/6 = 5{1}/3$ days
Question : 15 [SSC CGL Tier-I 2013]
2 men and 3 boys can do a piece of work in 10 days while 3 men and 2 boys can do the same work in 8 days. In how many days can 2 men and 1 boy do the work ?
a) 12$1/2$ days
b) 8 days
c) 7 days
d) 2 days
Answer »Answer: (a)
According to the question,
20 men + 30 boys = 24 men + 16 boys
4 men = 14 boys ⇒ 2 men = 7 boys
2 men + 1 boy = 8 boys
2 men + 3 boys = 10 boys
By $M_1D_1 = M_2D_2$
10 × 10 = 8 × $D_2$
$D_2 = {10 × 10}/8 = 25/2 =12{1}/2$ days
Using Rule 11,
Here, $A_1 = 2, B_1 = 3, D_1 = 10$
$A_2 = 3, B_2 = 2, D_2$ = 8
$A_3 = 2, B_3$ = 1
Required time = ${D_1D_2(A_1B_2 - A_2B_1)}/{D_1(A_1B_3 - A_3B_1) - D_2(A_2B_3 - A_3 B_2)}$ days
= ${10 × 8(2 × 2 - 3 × 3)}/{10(2 × 1 - 2 × 3) - 8(3 × 1 - 2 × 2)}$
= ${80 × -5}/{-40 + 8} = 12{1}/2$ days
IMPORTANT quantitative aptitude EXERCISES
-
Top 199+ Basic Time and Work Aptitude MCQs with Answers »
-
Top 200+ Time and Work Problem Solving By Formula Method »
-
New 189+ Time & Work MCQs Practice Test for BANK Exams »
-
Top 199+ Time & Work MCQs: Men Women Child for BANK Exam »
-
Top 199+ Time and Work Questions Test on Fraction of Work »
-
Top 199+ Time and Work Efficiency Based Aptitude MCQ Quiz »
-
New 299+ Time and Work Aptitude Test On Individual Wages »
Model 4 Working with Man, Woman, Child Shortcuts »
Click to Read...Model 4 Working with Man, Woman, Child Online Quiz
Click to Start..time & work Shortcuts and Techniques with Examples
-
Model 1 Basics on Time & Work
Defination & Shortcuts … -
Model 2 Formula method ‘M1D1W1 = M2D2W2’
Defination & Shortcuts … -
Model 3 Man leaves & joins
Defination & Shortcuts … -
Model 4 Working with Man, Woman, Child
Defination & Shortcuts … -
Model 5 Split & Fraction of work
Defination & Shortcuts … -
Model 6 Efficiency of the worker
Defination & Shortcuts … -
Model 7 Working with individual wages
Defination & Shortcuts …
quantitative aptitude CATEGORIES
RECENT BLOGS
Recently Added Subject & Categories For All Competitive Exams
Most Important Antonyms Vocabulary - IBPS Clerk Prelims 2024
Latest Antonyms multiple choice questions and answers with free PDFfor IBPS Clerk Prelims 2024. English Vocabulary practice exercise for all bank exam
Continue Reading »
Syllogism Practice Questions Answers PDF - IBPS Clerk 2024
Practice Verbal Reasoning Syllogism multiple choice questions and answers with Fully solved explanation, PDF for the IBPS Clerk Prelims 2024 Bank Exam
Continue Reading »
IBPS Clerk Prelims 2024 Synonyms Questions Solved Answers
Most important IBPS Clerk Prelims 2024 Synonyms and Antonyms multiple choice questions and answers with detailed solutions, English vocabulary PDF Download
Continue Reading »
New Cloze Test Questions and Answers PDF - IBPS Clerk 2024
The most important Cloze Test questions with detailed answers for upcoming IBPS Clerk prelims 2024. Latest English verbal ability practice MCQs, PDF
Continue Reading »